What's the speed?
Warning: trigonometry ahead
Here's another mathish problem for your enjoyment. There's no trick here, it's just a tough problem.
There are four points, A, B, C, and D. You wish to travel from point A to point C. You travel in a vehicle that, when it's engaged, only goes at exactly one speed; no more, no less.
You know that angle BCD = 90 degrees. You also know that the length of segment DC = 10 miles, and the length of BC also equals 10 miles.
There are three paths you can take to get from A to C:
Going from A straight to C takes 30 minutes.
Going from A to B to C takes 35 minutes.
Going from A to D to C takes 40 minutes.
See the following illustration (it's clickable):

For convenience, I've defined angle ACD as theta and angle ACB as 90-theta.
Find the speed of your vehicle.
I'll post a solution in a week or so.
**UPDATE**
Hong Kim busted up some trig and got the solution. Here's my solution to the problem. Hong, is this similar to the approach you took?
Here's another mathish problem for your enjoyment. There's no trick here, it's just a tough problem.
There are four points, A, B, C, and D. You wish to travel from point A to point C. You travel in a vehicle that, when it's engaged, only goes at exactly one speed; no more, no less.
You know that angle BCD = 90 degrees. You also know that the length of segment DC = 10 miles, and the length of BC also equals 10 miles.
There are three paths you can take to get from A to C:
Going from A straight to C takes 30 minutes.
Going from A to B to C takes 35 minutes.
Going from A to D to C takes 40 minutes.
See the following illustration (it's clickable):

For convenience, I've defined angle ACD as theta and angle ACB as 90-theta.
Find the speed of your vehicle.
I'll post a solution in a week or so.
**UPDATE**
Hong Kim busted up some trig and got the solution. Here's my solution to the problem. Hong, is this similar to the approach you took?

2 Comments:
.647 miles/min
38.84 mph
hong
Hong is 'da man!
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